Integrand size = 23, antiderivative size = 65 \[ \int \frac {\sin ^n(e+f x)}{(a+a \sin (e+f x))^{3/2}} \, dx=-\frac {\operatorname {AppellF1}\left (\frac {1}{2},-n,2,\frac {3}{2},1-\sin (e+f x),\frac {1}{2} (1-\sin (e+f x))\right ) \cos (e+f x)}{2 a f \sqrt {a+a \sin (e+f x)}} \]
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Time = 0.10 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {2866, 2864, 129, 440} \[ \int \frac {\sin ^n(e+f x)}{(a+a \sin (e+f x))^{3/2}} \, dx=-\frac {\cos (e+f x) \operatorname {AppellF1}\left (\frac {1}{2},-n,2,\frac {3}{2},1-\sin (e+f x),\frac {1}{2} (1-\sin (e+f x))\right )}{2 a f \sqrt {a \sin (e+f x)+a}} \]
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Rule 129
Rule 440
Rule 2864
Rule 2866
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {1+\sin (e+f x)} \int \frac {\sin ^n(e+f x)}{(1+\sin (e+f x))^{3/2}} \, dx}{a \sqrt {a+a \sin (e+f x)}} \\ & = -\frac {\cos (e+f x) \text {Subst}\left (\int \frac {(1-x)^n}{(2-x)^2 \sqrt {x}} \, dx,x,1-\sin (e+f x)\right )}{a f \sqrt {1-\sin (e+f x)} \sqrt {a+a \sin (e+f x)}} \\ & = -\frac {(2 \cos (e+f x)) \text {Subst}\left (\int \frac {\left (1-x^2\right )^n}{\left (2-x^2\right )^2} \, dx,x,\sqrt {1-\sin (e+f x)}\right )}{a f \sqrt {1-\sin (e+f x)} \sqrt {a+a \sin (e+f x)}} \\ & = -\frac {\operatorname {AppellF1}\left (\frac {1}{2},-n,2,\frac {3}{2},1-\sin (e+f x),\frac {1}{2} (1-\sin (e+f x))\right ) \cos (e+f x)}{2 a f \sqrt {a+a \sin (e+f x)}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(274\) vs. \(2(65)=130\).
Time = 3.32 (sec) , antiderivative size = 274, normalized size of antiderivative = 4.22 \[ \int \frac {\sin ^n(e+f x)}{(a+a \sin (e+f x))^{3/2}} \, dx=\frac {\sec (e+f x) \sin ^n(e+f x) \left (a^2 \operatorname {AppellF1}\left (1,\frac {1}{2},-n,2,\frac {1}{2} (1+\sin (e+f x)),1+\sin (e+f x)\right ) \sqrt {2-2 \sin (e+f x)} (-\sin (e+f x))^{-n} (1+\sin (e+f x))^2-\frac {4 a (-1+\sin (e+f x)) \left (1-\frac {1}{1+\sin (e+f x)}\right )^{-n} \left (2 a (1+2 n) \operatorname {AppellF1}\left (\frac {1}{2}-n,-\frac {1}{2},-n,\frac {3}{2}-n,\frac {2}{1+\sin (e+f x)},\frac {1}{1+\sin (e+f x)}\right )+a (-1+2 n) \operatorname {AppellF1}\left (-\frac {1}{2}-n,-\frac {1}{2},-n,\frac {1}{2}-n,\frac {2}{1+\sin (e+f x)},\frac {1}{1+\sin (e+f x)}\right ) (1+\sin (e+f x))\right )}{\left (-1+4 n^2\right ) \sqrt {1-\frac {2}{1+\sin (e+f x)}}}\right )}{8 a^3 f \sqrt {a (1+\sin (e+f x))}} \]
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\[\int \frac {\sin ^{n}\left (f x +e \right )}{\left (a +a \sin \left (f x +e \right )\right )^{\frac {3}{2}}}d x\]
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\[ \int \frac {\sin ^n(e+f x)}{(a+a \sin (e+f x))^{3/2}} \, dx=\int { \frac {\sin \left (f x + e\right )^{n}}{{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac {3}{2}}} \,d x } \]
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\[ \int \frac {\sin ^n(e+f x)}{(a+a \sin (e+f x))^{3/2}} \, dx=\int \frac {\sin ^{n}{\left (e + f x \right )}}{\left (a \left (\sin {\left (e + f x \right )} + 1\right )\right )^{\frac {3}{2}}}\, dx \]
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\[ \int \frac {\sin ^n(e+f x)}{(a+a \sin (e+f x))^{3/2}} \, dx=\int { \frac {\sin \left (f x + e\right )^{n}}{{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\sin ^n(e+f x)}{(a+a \sin (e+f x))^{3/2}} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {\sin ^n(e+f x)}{(a+a \sin (e+f x))^{3/2}} \, dx=\int \frac {{\sin \left (e+f\,x\right )}^n}{{\left (a+a\,\sin \left (e+f\,x\right )\right )}^{3/2}} \,d x \]
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